Question

What is the mass of 5.00 L of propane vapor (C₃H₈) at STP?

Answer 1

At STP condition: 1 mole of a gas= 22.4 L volume

Given:
\[ \rm 5.00L~~of~~C_3H_8 \]first we need to get rid of "L" how would we do that?
we know 1 mole of a gas = 22.4 L so
\[ \rm 5.00L~~C_3H_8 \cdot \frac{ 1~mole~C_3H_8}{22.4~ L~ C_3H_8} \]

Answer 2

\[ \rm 5.00 \cancel{L~~C_3H_8} \cdot \frac{ 1~mole~C_3H_8}{\cancel{22.4~ L~ C_3H_8}} \] L cancels out, left with
\[\rm 1 ~mole~C_3H_8\]
do you know how to convert moles to mass ??

Answer 3

1 mole of C₃H₈ = how many grams of C₃H₈?