Question

The vertices of triangle JKL, shown below, are J(2, 1), K(4, 4), and L(6, 2).
If triangle JKL is translated 2 units to the left and 4 units down, what are the new coordinates of Point L?

(10, 0)

(2, 0)

(8, –2)

(4, –2)

Answer 1

Someone please help.

Answer 2

🥺Please 🥺

Answer 3

Is there a picture? It says shown image

Answer 4

For all the points, you want to apply the transformations
J(2, 1), K(4, 4), and L(6, 2).
2 to the left and 4 down, so for every x coordinate, subtract 2 (because 2 to the left) and subtract 4 from every y-coordinate

Answer 5

An example of that would be J(2,1) So if you subtract 2 from 2 you have 0, and 4 from 1 you have negative 3,
So the translated form of J(2,1) is J'(0,-3)

Answer 6

Adding onto what darkknight said ofc

Answer 7

Heh I think i got it. Thanks Yall 🥺

Answer 8

np