Question

Richard simplified an expression in three steps, as shown below:

I will include picture below.

Which is the first incorrect step and why?

Step 1: all the exponents are multiplied by 3
Step 2: the exponents in the denominator are multiplied
Step 3: the exponents of the same base are subtracted during division
Step 3: the exponents of the same base are added during division

Answer 1

Please answer!

Answer 2

The pic might not be cleaar

Answer 3

idk why

Answer 4

Btw i answered b i just wanted to know if its right

Answer 5

kalihood do you think my answer is right?

Answer 6

That's what I see

Answer 7

hold up let me get a better one

Answer 8

what this one is the same

Answer 9

is it ok if i send it in text?

Answer 10

like this

Answer 11

It still looks exactly the same..

Answer 12

x to the power of negative 4 multiplied by y to the power of 2, over y multiplied by x to the power of 2 multiplied by x to the power of 2 multiplied by y to the power of negative 4, the whole to the power of 3 equals x to the power of negative 12 multiplied by y to the power of 6, over y to the power of 3 multiplied by x to the power of 6 multiplied by x to the power of 6 multiplied by y to the power of negative 12 equals x to the power of negative 12 multiplied by y to the power of 6, over y to the power of negative 36 multiplied by x to the power of 36 equals x to the power of negative 48 times y to the power of 42.

Answer 13

There you go.

Answer 14

i picked the second answer

Answer 15

To those who can't see it-

Answer 16

Yes that's what it is!

Answer 17

(I'll be going over these step by step, might take a bit)

But yes, B is correct. Because instead of adding powers to the same he multiplied the powers of same base in denominator.

Step one is he multiplied by three (3). \[\frac{ x ^{-4}y ^{-2} }{ yx ^{2}\times x ^{2} y-4 }^{3}=\frac{ x ^{-12}y ^{6} }{y ^{3}x ^{6}y-12 }\]

Answer 18

Instead of adding, he multiplied step two (2)
\[\frac{ x ^{-12}y ^{6} }{ y ^{3}x ^{6}\times x ^{6}y ^{-12}}= \frac{ x ^{-12}y ^{6} }{ x ^{12}y ^{-9} }\]

Answer 19

Wow, this is a great explanation man

Answer 20

Thank you for taking your time to write this

Answer 21

I'll keep all of this mind

Answer 22

And the exponents of the same base are subtracted during division \[\frac{ x ^{-12}y ^{6} }{ x ^{12}y ^{-9}}=x ^{-12-12}y ^{6+9}\]

Answer 23

Which he equaled it out to be\[=x ^{-24}y ^{15}\]

Answer 24

No problem