Question

Please help....with some trig..
Solve 2 sin(x)-2√3 cos(x)-√tan(x)+3=0 on[0,2π]

Answer 1

Wich class is dis for

Answer 2

so like a first idea note sin(x) = a and cos(x) an b and write tan(x) = sin(x)/cos(x)

so look what will get in this way

Answer 3

I'm not sure I understand what you're trying to tell me.

Answer 4

use what i ve said above and get

2a - 2sqrt3(b) - sqrt (a/b) +3 = 0

so there inside radical is just tan (x) or tan(x)+3 ?

Answer 5

tan(x)+3

Answer 6

ok than will be

2a +(2sqrt3)b - sqrt[(a/b) +3)] = 0

so but you need get an equation just with one variable - for this you can rewrite the cos(x) in function of sin(x) or viceversa the sin(x) in function of cos(x) using this equation

sin^2 (x) +cos^2 (x) = 1

Answer 7

so do you understand the way ? you need get an equation with just one variable

Answer 8

Ahhh I see.