Question

The coordinates of trapezoid EFGH are E(4, 6), F(2, 3), G(4, 2), and H(8, 4). The image of EFGH under dilation is E'F'G'H'.

If the coordinates of vertex G' are (2, 1), what are the coordinates of vertex H'? (1 point)
options:
1)
(4, 2)

2)
(2, 1)

3)
(4, 1)

4)
(6, 2)

(they didn't give me a graph for this or anything, just that text)

Answer 1

wait, since G(4, 2) became G(2, 1) after the dilation, would it H not be (4, 2)? or does it work differently?

Answer 2

so @jinqx than you see the coordinates of G(4)2) became G'(2,1) so how you think that was this dilation of trapezoid or why you think that after dilation would be for H' these (4,2) ?

i think you are in a right way but pls tel me why you think it so ?

Answer 3

Since it was a dilation, I was thinking I could just divide them by 2 but since this is a question from a pretest, I'm not entirely sure lmao!! since H' became (4, 2) and it was originally (8, 4) it leads me to think I should just divide by two and not subtract

Answer 4

so bc. the coordinates of G after dilation from (4,2) like halfed in (2,1) so in this way i think you can use the halving way for coordinates of H' after dilation

Answer 5

yea I see what u mean. so to figure out missing points for a dilation, would you always divide? or on others would you multiply?