Question

Two oranges and five lemons cost $2.95. Three oranges and two lemons cost $2.50. How much would five oranges and three lemons cost?

Answer 1

X= Cost of 1 orange
Y= Cost of 1 Lemon
5x + 3y- You need to find the Cost of 2 oranges and 5 lemons
3oranges and 2 lemons cost $2.95
2x +5y = 2.50
x= $6
y= $0.35

Answer 2

Try a website called brainly it can help you

Answer 3

its for school

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @POYO
its for school
\(\color{#0cbb34}{\text{End of Quote}}\)
promoting a hw site inside of another hw site

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1
X= Cost of 1 orange
Y= Cost of 1 Lemon
5x + 3y- You need to find the Cost of 2 oranges and 5 lemons
3oranges and 2 lemons cost $2.95
2x +5y = 2.50
x= $6
y= $0.35
\(\color{#0cbb34}{\text{End of Quote}}\)
MOst of the information was found on...https://softmath.com/algebra-word-problems/show.php?id=28563

Answer 6

well its for school

Answer 7

Oh ok thanks

Answer 8

@Astrid1 , that's not the complete answer :)

Answer 9

I got one more try left it said it was incorrect astrid

Answer 10

x= the cost of 1 orange
y= the cost of 1 lemon

2x+5y=$2.95
3x+2y= $2.50

To do this we need to use the substitution property
Once you work this out you get the following:
x=$0..6
y=$0.35

Now we plug this into the asked equation
5x + 3y = 5*0.6 + 3*0.35 = $4.05
5 oranges and 3 lemons= $4.05

Answer 11

Ok thank you

Answer 12

Anytime! :)

Answer 13

Convert had the complete work from Astrid1's website :)

Answer 14

@dontsaymyname I used https://softmath.com/algebra-word-problems/show.php?id=28563
and restated it in my own words.