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Math Image Attached, plz help
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0-0
(5, 0) is a point, so when 5 is plugged into x the result has to be 0 right? for y i mean so a(x-h)^2 is x=5 then a(5-h)^2 the only way you can get y=0 is h also equals 5
do you understand that?
y = a(x-h)^2 where h = 5 y = a(x-5)^2 if we plug in 10 for x, then y = a(10-5)^2 y = -15 so -15 = a(5)^2 -15 = 25a a = -15/25
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thats how we solved for a and h, plug those values in so y = (-15/25)(x-5)^2
Ty, but should -15/25 be simplified??
@darkknight
0-0
He left.
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0-0, do yall think I should simplify the -15/25?
welp.
I'm not really sure tbh.
Ig, ill simplify :/
Ok good luck.
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Thxs
np
ofc it should, but it doesnt really matter, yeah its kinda intuitive, simplify always
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