5(- 3x - 2) - (x - 3) = -4(4x + 5) + 13
Do I just solve it, @CocoCammron?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie Do I just solve it, @CocoCammron? \(\color{#0cbb34}{\text{End of Quote}}\) yeah
Is there answer choices?
No
Is there a way you can show what it's asking, please?
I think we're just solving \(5(- 3x - 2) - (x - 3) = -4(4x + 5) + 13\)
what did you get and i can tell you if you were correct
It is a homework assiment THere is no answer choices
Infinitely Many Solutions
\(\color{#ffff4d}{\text{Originally Posted by}}\) @sddqdqd Infinitely Many Solutions \(\color{#ffff4d}{\text{End of Quote}}\) Please provide how you got your answer.
\(5(−3x−2)−(x−3)=−4(4x+5)+13\) Simplify, both sides and distribute the`-` sign, \(5(−3x−2)+−1(x−3)=−4(4x+5)+13\) \(5(−3x−2)+−1x+(−1)(−3)=−4(4x+5)+13\) \(5(−3x−2)+−x+3=−4(4x+5)+13\) Distribute: \((5)(−3x)+(5)(−2)+−x+3=(−4)(4x)+(−4)(5)+13\) \(−15x+−10+−x+3=−16x+−20+13\) Combine the like terms: \((−15x+−x)+(−10+3)=(−16x)+(−20+13)\) \(−16x+−7=−16x+−7\) \(−16x−7=−16x−7\) \(+16x\) to both sides \(−16x−7+16x=−16x−7+16x=\) \(−7+7=−7+7\) \(0=0\), true
^ i got mine the same way
However, that would only mean all real numbers are solutions.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @umm However, that would only mean all real numbers are solutions. \(\color{#0cbb34}{\text{End of Quote}}\) I know. Thanks.
Yes, I was explaining to @sddqdqd since their answer was infinitely many solutions.
since both sides equal, there are infinitely many solutions.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @umm Yes, I was explaining to @sddqdqd since their answer was infinitely many solutions. \(\color{#0cbb34}{\text{End of Quote}}\) Oh right.
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