Write a linear equation to find the attendance(in millions) Y after X years let X be the number of years since 2000.
@ramen
@umm
you basically just have to find the slope, do you know what this is?
take any 2 points on the table, find the slope. remember x is years after 2000
Is that the problem you have in the screenshot? If so I think it walks you through the problem.
23 is my prob
pick two points first
randomly?
Yes.
Any 2 points from the table.
9.71, and 9.97
points have an x and a y coordinate. those aren't points
well also list the years (y-coordinates)
(x,y) is how u list a coordinate.
oh yeah, yeah, got that
(9.71, 9.97) like this?
Yup now list the other coordinate.
the years?
Well we meant like 2 coordinates such as (x,y) and (x,y). You only listed one coordinate.
no she did not list a coordinate, (x1, y1) and (x2, y2) we are looking for where x1 and x2 are x coordinates and y1 and y2 are their y-coordinates respectively
So, what does" let X be the number of years since 2000." mean?
Is 2000 my other coordinate for x? As in, x1 and x2
Oh, nvm I already got it!
Well so when it says let x be the number of years since 2000, it refers to the x coordinates in the table.
y=1/5x+4
Is what it came out to be
Just making sure is this the table? vvvvv
Yes
Ok let me walk you through pick 2004, 9.97 and 2006, 9.71 when we write this as x is years after 2000 4,9.97 and 6, 9.71 now slope formula \[(9.97-9.71)/(4-6)\] simplify this slope value and then use point slope form or solve for the y-intercept. lmk if u need more clarification
Just to clarify, x years after 2000 means how ever many years after 2000. For example for 2004, that is 4 years after 2000 so the x coordinate would be 4.
Yayyyy mdobbs changed her pfp
You have to find the slope, and take any 2 points on the table if im correct.
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