does anyone know how to solve special right triangles?
Did you already get help?
no i didnt
Okay I can help-
i just need an explanation on how to do it, thank you!
Okie dokie... so do you know the Pythagorean Theorem ?
um just a little not alot
Well the Pythagorean Theorem is a^2+b^2=c^2.
Do you know what a hypotenuse is ?
yes i do
Ok, well the c^2 part is the hypotenuse in the equation. Lemme draw you something rq.
okay
|dw:1610994606613:dw|
so... that big side is the c^2.
ok got it
how would you go about finding the missing sides of the triangle?
Ok, well I just went on a whole different route... Ignore all that. Ok here's what you really need to know. Lemme draw another thing rq.
|dw:1610994843730:dw|
this is the equation we're going to start with.
okay
Ok to start off... we need to identify all the angles of the triangle.
Can you tell me what the angles are?
45,45,90
Okay... well there is different rules for (45.45.90) and (30,60,90) triangles.
In a 45,45,90... the legs (the other sides other than the hypotenuse) are found by dividing the hypotenuse by \[\sqrt{2}\]
To find the hypotenuse, you multiply the legs by \[\sqrt{2}\]
|dw:1610995249005:dw|
You find the "long side" by multiplying the side by the square root of 2.
but where did the 1 come from
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie but where did the 1 come from \(\color{#0cbb34}{\text{End of Quote}}\) The 1 is the measure of the side, not the hypotenuse.
why are these triangles special right triangles ?
Don't think too hard... the 1 is just the measure of the side, that's all.
oh okay
|dw:1610995533163:dw|
just use the law of sin or cos and solve them but you need to know the trigonometrical value of sin 45° or cos 45° and so much
|dw:1610995661772:dw|
4?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie 4? \(\color{#0cbb34}{\text{End of Quote}}\) Correct~
So now you have the answer to your first question.
Wait wait wait-
We still need to find B- but in a 45, 45, 90 triangle... the 2 sides are the same, EXCEPT for the hypotenuse.
okay, these are so hard there is still 4 more after this ill try to figure them out
Do you want me to go slower ? What can I do to help ?
no its fine its just confusing to me thats all
Ok... well we're gonna try the 2nd one, lemme draw it rq-
|dw:1610996001783:dw|
what are the angles in the triangle ?
45,45,90
|dw:1610996114904:dw|
Special right triangles follow the form 45, 45, 90 or 30, 60, 90 These are angle measures and their corresponding side lengths are \[x, x, \sqrt{x}\] and \[x, x \sqrt(3), 2x\] respectively
For example if you are given a 45-45-90 triangle, and they say the length of a side opposite one of the 45 degree angles is 5, the side opposite the other 45 degree angle is also 5 and the hypotenuse is \[5\sqrt{2}\]
the legs are missing btw
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie the legs are missing btw \(\color{#0cbb34}{\text{End of Quote}}\) Ok remember how I said that the legs are equal in a 45, 45, 90 ? Well, that means x and y are equal, so let's solve for the legs...
in that case other way around. If you know hypotenuse in a 45-45-90 triangle the legs are equal to the hypotenuse divided by sqrt(2)
so when you divide the hypotenuse by that you are given the legs?
|dw:1610996401835:dw|
so my opinion that all what you need to know - the law of sin and cos and that sin45° = cos45° = \[\frac{ \sqrt{2} }{ 2 }\]
for a 45-45-90 degree yes @nevaehhh
correct @jhonyy9 think about how the 45-45-90 is defined on a unit circle. You take the sin(45) which is the opposite/hypo|dw:1610996612703:dw| then sin(45) = x/1 so x = sin(45) = sqrt(2)/2
if yall could let me have this one- you see im only 47👉🏼👈🏼
thats the case for the hypo being 1 if the side was 1 then we divide the hypo by sqrt(2)/2 or multiply by 2/(sqrt(2)) to get us the value
\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight Special right triangles follow the form 45, 45, 90 or 30, 60, 90 These are angle measures and their corresponding side lengths are \[x, x, \sqrt{x}\] and \[x, x \sqrt(3), 2x\] respectively \(\color{#0cbb34}{\text{End of Quote}}\) which is where this comes in
I feel bad for not understanding still, im confused again
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie I feel bad for not understanding still, im confused again \(\color{#0cbb34}{\text{End of Quote}}\) what are you confused about ?
@nevaehhh feel free to help out. \(\color{#0cbb34}{\text{Originally Posted by}}\) darkknight \(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight Special right triangles follow the form 45, 45, 90 or 30, 60, 90 These are angle measures and their corresponding side lengths are \[x, x, \sqrt{x}\] and \[x, x \sqrt(3), 2x\] respectively \(\color{#0cbb34}{\text{End of Quote}}\) which is where this comes in \(\color{#0cbb34}{\text{End of Quote}}\) use this for it
Just solve the equation I gave you... look at the drawing rq.
|dw:1610996906591:dw|
is it 2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie is it 2 \(\color{#0cbb34}{\text{End of Quote}}\) Around 2.83 to be exact
But... what does this mean ? What do x and y equal ?
the 2.83
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie the 2.83 \(\color{#0cbb34}{\text{End of Quote}}\) good job- x=2.83 and y=2.83
Do you want me to do the next question with you ?
can i try to solve it then you tell me if its right?
Absolutely.
yea i need help with this one the hypotenuse is confusing
i mean the leg sorry
You were right the first time, we're solving for the hypotenuse-
wait what do you multiply again the find the hypotenuse.
to*
|dw:1610997295994:dw|
|dw:1610997415055:dw|
so 3?
Yep- that's right
3 would be the hypotenuse and the other equation would be the leg
Yep- the other leg would equal the other one lmao-
ohhhhhh
But the hypotenuse is 3.
ok i got it noww
Okie dokie~ hope i helped lmao
you did so much thank you!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie you did so much thank you! \(\color{#0cbb34}{\text{End of Quote}}\) you're welcome :)
u need to be promoted girl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie u need to be promoted girl \(\color{#0cbb34}{\text{End of Quote}}\) PREACHHH- i really do smh😭
yessss fr omg
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