Write an equation in slope-intercept form of the line with the given characteristics through: (-3,1) slop=2
General slope-intercept form is written as \(y=mx+b\) They give you the slope and a point Points are written as (x,y) First start off by substituting what they gave you
ok
then?
Once you have that then you can solve for b Do you know how to substitute and solve for it?
no not really im not really in school that much so no i guess not
Ah Substituting just means switching the variable (or letter for whatever number they give you) In this case, they told you slope = 2 So you would do \(y=2x+b\) Does that make sense?
umm i guess
Hmm what confuses you?
math
Haha in specific?
idrk
Don't think too hard on it You're just switching numbers and letters \(y=mx+b\) y = y value m = slope x = x value b = y-intercept We started out with slope So \(y=mx+b\) becomes \(y=\color{red}2x+b\) Yes?
yes
Nice Now, we have point \((-3,1)\) Points is the same as saying \((x,y)\) This would mean -3 is our "x value" and 1 is our "y value" Do you know how to substitute them into the equation now?
i think so yeah
Go ahead and try it (I'll let you know if its good or if it needs a fix)
ok thx
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