2(a+3)=-4 A.) -5 B.) -2 C.) 3 D.) 4
There that's better
Yeah so the first step would be to distribute so we already have \(2(a+3)=−4\) \((2)(a)+(2)(3)=−4\) Which equals what?
Basically all you're doing is solving the multiplication (2)(a)+(2)(3)=−4 ^ ^ 2xa 2x3
Is this adding
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Lilian9667 Is this adding \(\color{#0cbb34}{\text{End of Quote}}\) multiplication
or Multiplication
Multiplication
ohh
lol
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie Yeah so the first step would be to distribute so we already have \(2(a+3)=−4\) \((2)(a)+(2)(3)=−4\) Which equals what? \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{Originally Posted by}}\) @supie Basically all you're doing is solving the multiplication (2)(a)+(2)(3)=−4 ^ ^ 2xa 2x3 \(\color{#0cbb34}{\text{End of Quote}}\)
Confused...?
here give me a moment hmm?
ight
12? and where's the post to be by the 2x a<
I mean whats the a post to be by the 2
What?
it says 2xa <
a <<<<<
All you're doing is multiplying 2 and \(a\) and multiplying 2 and 3
Confused...again....?
Yah
So we're multiplying 2 and 3 which is 6 and 2 and a which is 2a so that would leave is with \(2a+6=−4\)
6
oh so it's 4
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Lilian9667 oh so it's 4 \(\color{#0cbb34}{\text{End of Quote}}\) what's 4?
Haha Nevermind
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Lilian9667 Haha Nevermind \(\color{#0cbb34}{\text{End of Quote}}\) lol ok
I thought that was the answer
So now do you know the next step what we have to do to \(2a+6=−4\)?
no
Ok so we have to change the `+` to a `-` and we have to take the `6` and subtract it from both sides of the equation the reason we `subtract` is because we changed the `+` to a `–`
So we changed the plus to a minus no we're subtracting 6 from both sides of the equation \(2a+6−6=−4−6\) so that equals what?
Still confused....?
Oh sorry just asking my mom about this question
Oh ok
yah She said to go to khan academy? I guess
CUS THIS IS HARD DON"T KNOW HOW YOU CAN DO THIS
Huh
|dw:1611160582576:dw|
-5
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Lilian9667 -5 \(\color{#0cbb34}{\text{End of Quote}}\) yeah good job
yes
You can close this now @Lilian9667
Ok
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