4x−25=20
what do you think x stands for?
We're solving for \(x\)
Do you know the first step? @WavyML
y=mx+b is the equation you need to go by.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Timmyspu y=mx+b is the equation you need to go by. \(\color{#0cbb34}{\text{End of Quote}}\) no? that is for slope
that was fast
\(\color{#0cbb34}{\text{Originally Posted by}}\) @WavyML that was fast \(\color{#0cbb34}{\text{End of Quote}}\) what was fast?
all your responses
ok so what are the steps?
So the first step is to \(+25\) to both of the sides of the equation which would look like this \(4x−25+25=20+25\) do you know what that equals?
@jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie So the first step is to \(+25\) to both of the sides of the equation which would look like this \(4x−25+25=20+25\) do you know what that equals? \(\color{#0cbb34}{\text{End of Quote}}\) Trust supie he knows how do do this.
yea
11.25
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie So the first step is to \(+25\) to both of the sides of the equation which would look like this \(4x−25+25=20+25\) do you know what that equals? \(\color{#0cbb34}{\text{End of Quote}}\) @WavyML So simplify \(4x−25+25=20+25\) what did you get?
wait look at the question again I made a mistake sry
x=11.25
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Kd6009886 x=11.25 \(\color{#0cbb34}{\text{End of Quote}}\) You can not give direct answers.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @WavyML wait look at the question again I made a mistake sry \(\color{#0cbb34}{\text{End of Quote}}\) I don't see a mistake....
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Timmyspu \(\color{#0cbb34}{\text{Originally Posted by}}\) @Kd6009886 x=11.25 \(\color{#0cbb34}{\text{End of Quote}}\) You can not give direct answers. \(\color{#0cbb34}{\text{End of Quote}}\) opps
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie \(\color{#0cbb34}{\text{Originally Posted by}}\) @WavyML wait look at the question again I made a mistake sry \(\color{#0cbb34}{\text{End of Quote}}\) I don't see a mistake.... \(\color{#0cbb34}{\text{End of Quote}}\) Or anything changed
Bc it didnt make the change it supposed to be 4x-2/5=20
Ok so we are supposed to solve it the exact same way but you have to divide first.
Oh ok well then the first step would be to add \(\frac{2}{5}\) to both sides Which would look like this; \(\LARGE 4x+\frac{-2}{5}+\frac25=20+\frac25\) So what would that equal?
...ig ur confused so that would equal \(\frac{102}{5}\) idrk how to explain addition... So now we have \(\bf 4x=\frac{102}{5}\) So then the next step is to divide both of the sides by 4 so \(\div 4\) to both sides \(4x/4=102/5/4\) So then \(\cancel{\frac{4x}{4}}\) (meaning that it cancels So all you have left is \(102/5/4\) simplify that, then you'll have your answer.
thx @supie
np
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