Can anyone vhere gelp me with simplex method pleaseeee

details ?

I dont know how to make equations

what nr. problem from these ?

Do anyone one of these which ever u find easy

hmmm...

what that?

@jhonyy9 can you do it?

is there a problem I can try to do?

Y'all dont have to solve it entirely. Just make the equations for me from this word problem

whats the word problem?

\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilaspie7 is there a problem I can try to do? \(\color{#0cbb34}{\text{End of Quote}}\) Yeah I've attached the pictures of it

ok

Number 29) Food 1 = 7c/u (grams of carbo's per unit) Food 2 = 4 c/u (grams of carbo's per unit) 500 calories of each meal. at least 210 must be protein Food 1 and 2= 100cal/u (calories per unit) food 1 = 30 Pcal/u (protein calories per unit) food 2 = 50 Pcal/u (protein calories per unit) All the info in the problem broken down above

I am not sure what the simplex method is but I know how to do this in another method called optimization, which is a calc thing so sorry if you aren't in calc yet I can try to do it the non-calc way is you aren't in calc

In order to perform optimization step 1) draw a pic and label variables and constants 2) Determine what you are trying to maximize/minimize and write an eqn for it 3) If more than 2 variables find another eqn to eliminate extra variables 4) test critical points/endpoints to find the absolute max/min value

Now we are finding how many units of each food he needs to eat to MINIMIZE the amount of carbohydrates. This is Step 2

Now how much calories he has to consume of each meal we should represent with a variable (y1 for meal/food 1 and y2 for meal/food 2) \[y1 \ge500 \]\[y2 \ge500 \] Now \[y1 = y2 = 100\cal/u\] \[y1 = 30Pcal/u\]\[y2 = 50Pcal/u\] Fairly sure these are all the eqns we will need

hmm... lets convert grams to calories to make life easier. 7 grams = 28 calories 4 grams = 16 calories

Now critical points, 5 will be a minimum because at least 500 calories at each meal he should consume, and both foods contain 100 calories per unit so 5 units later he would meet the requirements

This is per food btw, so really we are optimizing 2 equations for each of the food scenarios, I grouped them together above so don't be confused

actually disregard the thing I said about critical points, for example food 1, at least 210 calories must be protein, since food 1 gives only 30protien calories per unit the critical value is 7. and 5 is critical value for food 2

eqn for minimum protein calories\[30x \ge210\] eqn for mi total calories\[100x \ge500\] eqn for minimum carbohydrate calories \[7x\] (x) here is the number of units for FOOD 1, I just changed the variables up to not confuse myself. Apparently I only have 1 variable thonk... so either I did sum wrong or this wasn't an optiization problem, well out of the first 2 equations 7 is the minimum number that satisfies both requirements, so 7 for x, now that would result in 49 min carbo calories. So the answer was 7 units of food 1 he should eat to minimize the amount of carbohydrates and with 7 units he would be consuming 49 carbo calories. Now you try for food 2

@Andaleeb also confirm if I am doing the right thing, something similar to what your teacher does...

Thankyouu for the detailed answer. Simplex method is a bit different but i got the idea

you lucked out

?

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Andaleeb Thankyouu for the detailed answer. Simplex method is a bit different but i got the idea \(\color{#0cbb34}{\text{End of Quote}}\) well no problem I tried my best. Gl : )

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