Question

Factoring - Picture provided below

Answer 1

Solving 3x2-13x+4 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC
x = ————————
2A

In our case, A = 3
B = -13
C = 4

Accordingly, B2 - 4AC =
169 - 48 =
121

Applying the quadratic formula :

13 ± √ 121
x = ——————
6

Can √ 121 be simplified ?

Yes! The prime factorization of 121 is
11•11
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 121 = √ 11•11 =
± 11 • √ 1 =
± 11

So now we are looking at:
x = ( 13 ± 11) / 6

Two real solutions:

x =(13+√121)/6=(13+11)/6= 4.000

or:

x =(13-√121)/6=(13-11)/6= 0.333


Two solutions were found :
x = 1/3 = 0.333
x = 4

Answer 2

This was incorrect, but thanks for trying <3

Answer 3

incorrect why ?

Answer 4

x = 1/3 and x = 11 are the roots of this posted quadratic

Answer 5

I put the answer provided, and it was incorrect, the answer was 2, -22/3

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ZombieLover
Solving 3x2-13x+4 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC
x = ————————
2A

In our case, A = 3
B = -13
C = 4

Accordingly, B2 - 4AC =
169 - 48 =
121

Applying the quadratic formula :

13 ± √ 121
x = ——————
6

Can √ 121 be simplified ?

Yes! The prime factorization of 121 is
11•11
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 121 = √ 11•11 =
± 11 • √ 1 =
± 11

So now we are looking at:
x = ( 13 ± 11) / 6

Two real solutions:

x =(13+√121)/6=(13+11)/6= 4.000

or:

x =(13-√121)/6=(13-11)/6= 0.333


Two solutions were found :
x = 1/3 = 0.333
x = 4
\(\color{#0cbb34}{\text{End of Quote}}\)
yes bc this is wrong equation not is what you posted

3x^2 +16x -44 = 0

this is the correct posed quadratic

Answer 7

Thank you!

Answer 8

np

yw