can anyone help me
Mkay, im gonna explain how to do it
3^4 ____ 3^2 When you have an exponent you take that number and multiply the leading number by itself that many times So, 3*3*3*3 _______ 3*3 You then cross out how many there are at the bottom from how many there are at the top leaving you with, 3*3 and as we should know, 3*3= 9
well you need to figure out the exponents first
and 3 to the second power is 9 right
and 3 to the fourth power is 81
so you have \[\frac{ 81 }{ 9 }\]
and when you simplify that what do you get
you would divide 81 by 9 and you would get 9 so you answer would be B. 9
So when you have an exponent for example if I had \(\color{yellow}{2}^\color{red}{3}\) then I would multiply `2` by itself `3` times because 3 is the exponent meaning that we have to multiply the other number by itself however much times the exponent says, if that makes sense. So in this case we have \(\frac{3^4}{3^2}\) which is basically \(3^4 \div 3^2\) \(\frac{3^4}{3^2}\) equals \(\frac{3 \times 3 \times 3 \times 3}{3 \times 3}\) because the exponent it `4` so you would have to multiply `3` by itself 4 times (numerator) and the same rule for the denominator, the exponent is 2 so you would have to multiply `3` by itself twice. So basically \(\LARGE\frac{3^4}{3^2}=\frac{3 \times 3 \times 3 \times 3}{3 \times 3}=\frac??=?\) or \(3^4รท3^2=?\) @zissette
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