What does (g4*34)-y4 =?
do you mean \[(g^4 * 3^4 ) - y^4\]
Yes
Is here a ss with the full problem?
I don' t know yet
So that’s all you know?
Not really i just need some of it
Ok but can you screenshot the problem and post it here?
yes
Ok thank you
The screenshot you pasted is different than what you originally posted. But even then, what is the exact question? What are the instructions?
Yeah I’m kinda confused on the way it was presented
To look and solve my teach has problem and i dont know how to solve it
Does she want you to graph the function?
Yes but not to much because itll confuse us
so do you know what odd and even numbers are?
Not in this sertin equation
so do you agree that some odd numbers are: 1, 3, 5, 7, ... some even numbers are: 2, 4, 6, 8, ...
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Brooklyngreen Yes but not to much because itll confuse us \(\color{#0cbb34}{\text{End of Quote}}\) @AZ do you understand this answer on your question ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Does she want you to graph the function? \(\color{#0cbb34}{\text{End of Quote}}\) on this ...
I think she's saying that she has to graph it but doesn't need to graph too many points so they don't get confused
Does she want you to graph the function? Yes but not to much because itll confuse us
This is what i mean yes
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ I think she's saying that she has to graph it but doesn't need to graph too many points so they don't get confused \(\color{#0cbb34}{\text{End of Quote}}\) ok
So let's do odd numbers first when we have odd numbers, we have to put it into f(n) = 3n + 1 when n is 1, what do you get? basically what is (3*1) + 1
Okay
ohh now i get it
and for even numbers, we have to use f(n) = n/2
thats why i was getting confused thanks for the help you guys
No problem!
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