i need help
with?
with the same thing?
hmmmmm
i can maybe help
ok
Find the radius or diameter of each circle with the given dimensions
then after that
how do i do that?
ummmmm
you have to
acute, means smaller than 90 degress. Right means equaling 90 degrees and obtuse means larger than 90 degrees
d=18in. i need t find the radius or the diameter
ok
so how do i find that out?
i think you have to look at the circles
A = πr2 = π(d2)2 A = C24π π = 3.1415 A = area C = circumference or perimeter r = radius, d = diameter
you get it?
not really
oh me either
hold up
r = 9 d = 18 C = 56.6
you get it?
so d=18 is 56.6?
idk
so, the circumference of a circle, weusually say is 2pir, but in this instance, because it's all diameter, it would be easier to say that teh circumberence is dpi, so, diameter times 3.14
so, for the first one, just multiply 18 by 3.14
for the ones that are radius , multiply it by 2, and then multiply it b 3.14 for 5-10 it's the same, make sure you know the difference between diameter adn radius tho
14-17 is the same, but read it carefully
56.52 for 1
i will try to help
if you want
lol, don't tell me answers, i'm not going to do it tbh but just use dpi or 2pi r bye-a
?
so confusing
ur not the one who's asking so ur spamming lol
how are you suppose to help me then
bc i just told you how to do it.... the process is more important than the result for this
actually, for the last one, besides for finding the circumference, you'll also need to divide but regardless of that, first do the first 4
the first one, how would you do it
which part of diameter times 3.14 or radius times 2 times 3.14 confuses you?
for the first one just multiply 18 by 3.14, which as you said is 56.62 inches for teh second , multiply 29 by 3.14, which is 91.06 meters for the third21*2*3.14=131.88 feet the fourth is 13*2*3.14= 81.64 millimeters do you know the difference between diameter and radius?????
thanks guys so much i got the help i needed from you sayin 'im helping'
I'm sorry
\(\color{#0cbb34}{\text{Originally Posted by}}\) @skrtkobainn thanks guys so much i got the help i needed from you sayin 'im helping' \(\color{#0cbb34}{\text{End of Quote}}\) i did help, your welcome lmaooo
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 then why would you say that you would help... \(\color{#0cbb34}{\text{End of Quote}}\) but then i tried 5 times and got it right only 2
judethedude your fine your the only one helping me
Really oh thanks
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