An angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5 cm long. A second side of the triangle is 6.9 cm long. Find the longest and shortest possible lengths of the third side of the triangle. Round answers to the nearest tenth of a centimeter. A. 41.4 cm, 8.3 cm B. 30 cm, 5.8 cm C. 41.4 cm, 4.3 cm D. 8.3 cm, 5.8 cm
BD/DC=6/5=AB/AC, in which AC=6.9, then we solve for AB=AC*6/5=8.28
BD/DC=6/5=AB/AC, where AB=6.9, then we solve AC=AB*5/6=5.75,
So have you gotten the answers-
nope. still confused. srry
So what did i say the answer was to both those problems we just solved-
ohhhhhhh. I get it now. if i round up then it would be D. 8.3, 5.8
BD/DC=6/5=AB/AC, in which AC=6.9, then we solve for AB=AC*6/5=8.28 like he said If you ever neeed help just ask one of us or tag anyone
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