A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy? fraction 3 over 8 fraction 4 over 8 fraction 5 over 8 fraction 6 over 8
I say its the first one
ye, but do you know why?
Can you give an explanation?
kk
so, you see that there are 3 flavors, orange, strawberry, pineapple orange has a 2/8 probability of getting pulled strawberry has 3/8 you see that they're both _/8, so there must be 8 in all, which means that there are 2 orange candies, 3 strawberry, and x pineapple so, just subtract 3 and 2 from 8, which is 3
Thank you. thats a great explanation.
yw~
so smart ~
@AZ
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 so, you see that there are 3 flavors, orange, strawberry, pineapple orange has a 2/8 probability of getting pulled strawberry has 3/8 you see that they're both _/8, so there must be 8 in all, which means that there are 2 orange candies, 3 strawberry, and x pineapple so, just subtract 3 and 2 from 8, which is 3 \(\color{#0cbb34}{\text{End of Quote}}\) technically, it doesn't mean that there must be 8, it could be some multiple of it
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