Question

Determine the equation of the graph, and select the correct answer below. (5 points)

parabolic function going up from the left through the point approximately negative two and three fourths comma zero and turning at the point negative one comma three and going down through the point zero comma two and through the point approximately three fourths comma zero and continuing towards infinity
Courtesy of Texas Instruments

Question 3 options:

1)

y = −(x + 1)2 + 3

2)

y = −(x − 1)2 + 3

3)

y = (x + 1)2 + 3

4)

y = (x − 1)2 − 3

Answer 1

ok soo u need help

Answer 2

yes

Answer 3

so they want a piont slope form equation

Answer 4

do yk how to find those

Answer 5

no, i just started the lesson and dont understand how to do them.

Answer 6

y-y₁=m(x-x₁)

Answer 7

so do u remember how to find slope

Answer 8

y=mx+b?

Answer 9

no thats slope intercept form, what we are looking for is point slope form which is y-y₁=m(x-x₁)

Answer 10

oh, ok

Answer 11

so basically u need to find the slope of this graph

Answer 12

then this should be very easy

Answer 13

do you know how to find slope

Answer 14

Ok, i cant remember

Answer 15

slope is y2-y1 and x2-x1

Answer 16

so do meh a favor and pick two points on your graph

Answer 17

(2,-3) (2,2)

Answer 18

mk so use what i just showed u and calculate tht

Answer 19

ok

Answer 20

do that

Answer 21

2-(-3) = 5
2-2 0

Answer 22

yep so ur slope is what?

Answer 23

dang moderator go away i aint dooin nun bad

Answer 24

(5,0)

Answer 25

yes

Answer 26

dammn now im stuck

Answer 27

so ik its d or c

Answer 28

Ok, so now i put my numbers in to this form y-y₁=m(x-x₁)

Answer 29

yes

Answer 30

Thank you

Answer 31

yes u do

Answer 32

no prollem

Answer 33

anytime u need help just hmu or dm me

Answer 34

that's wrong

Answer 35

this is a quadratic equation

Answer 36

how am i wrong

Answer 37

ii learned dis Butter

Answer 38

not a linear line so we don't use \( y - y_1 = m(x-x_1)\)

we have to use
\(y = (x -h)^2 + k\)

Answer 39

(h, k) is the vertex of your line

and which way does your parabola open? Is it up or down?
If it's opening up like U then it's positive

if it's opening down, then it'll be \(y = - (x-h)^2 + k\)

where (h, k) is your vertex

Answer 40

it opens down so i would have to use y= -(x-h)^2+k

Answer 41

so where do i get h and k

Answer 42

(h, k) is the point which is the vertex

Answer 43

Ok, thank you

Answer 44

No problem!