Graph the parabola. *POSTING EQUATION* Plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then click on the graph-a-function button.
\[y=x^2+4\]
Do you want to use desmos? That would be the easiest Or, we could also plug in random values of x
desmos is fine; im not really familiar with it tho
Okay, well, it would be good for you to know how to do it anyways. So, let's not use desmos for now
Do you think you know how to find the vertex?
Yes or no lol
Do you know what the function of the graph of x^2 looks like?
no
i- one sec
Do you know what a parabola is?
sorta..yea ive taken algebra 1, geometry, liberal arts, and math for college readiness and im still lost in all math; im familiar with it
If you've taken algebra 1, you should know what a parabola is
That, is the parent function of ^^^
ok.. now what?
So, +4, it would be a vertical shift, which means it goes up by 4 units So, do you know where teh vertex would be?
You could just tell me yes or no
yes
Then what is the coordinate point
im not sure
I- then why'd you tell me yes-
The vertex of the parent function, x^2, is the origin. As I've said before, adding the +4 in this is a vertical shift, so it goes up 4. So, the vertex is (0,4)
Get that? maybe? no?
@artlover03, it would be nice if you replied each time-_-
So then, we have two points to the left of the vertex, and two points to the right of the vertex. Then click on the graph-a-function button.
So, since this is symmetrical to the y-axis Whatever negative x value you plug in, the absolute value of that, and the y value stays the same For example, if I put in -2 or 2, the y for both is 8
So, i already gave you two points You can use another random value and plug it in
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