A pool measuring 16 meters by 20 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the pool and the path combined is 1152 square meters, what is the width of the path?
Can you attach the figure? @dmoscoso
So I'm assuming the diagram is something like this |dw:1615528018210:dw|
Ah okay, exactly what I was imagining it to be
so the area of a rectangle = length * width the length of the pool is 20 meters and now we added x meters on one side and x meters on the other side the width of the pool is 16 meters and similarly we added x meters on both sides
so we get the equation (20 + x + x) * (16 + x + x) = 1152 they told us 1152 was the area of the pool and the path surrounding it
can you simplify what's in the parenthesis first?
I cant figure it out.... I'm stuck on this one :(
Sure! Do you understand what I've done so far? Or would you like me to begin from the beginning
I understand so far
Great! So what is 20 + x + x what is x + x =
think of it like what is 1 apple + 1 apple
so I got this so far (16+2x)(20+2x)=1152
Good! So do you know how to multiply it Do you know the FOIL method? \( (a+b)(c+d) = ac + ad + bc + bd\)
okay so I got this 320+72x+4x^2
Great!! Now don't forget that it equals 1152 so let's just rearrange the terms 4x^2 + 72x + 320 = 1152 subtract 1152 on both sides so that way we can have it equal to 0 and then we can solve the quadratic equation what do you get when you subtract 1152 on both sides?
11522-320=832
I meant 1152-320=832
be careful, we're subtracting 1152 from 320 so it should be 320 - 1152
4x^2 + 72x + 320 = 1152 4x^2 + 72x + 320 - 1152 = 1152 - 1152 4x^2 + 72x + 320 - 1152 = 0 what is 320 - 1152=
-832
Good so now we have 4x^2 + 72x -832 = 0 how do you want to solve the quadratic equation? We can use the quadratic formula or we could even graph it The quadratic formula is \( x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \) when the equation is \( ax^2 + bx + c = 0\)
quadratic formula
okay, so a = 4 b = 72 and c = -832 you'll have to plug it in (if you ever want to do graphing, you can use https://www.desmos.com/calculator it's a really nice graphing website)
thanks for the website. so we got x=8,-26
yes and so can the width be a negative number? It's like time, can we ever have negative time? So can we ever have negative distance? So basically, our answer is just the positive number
8
That's your width!
THANK YOU!!! appreciate the step by step
It was my pleasure!!! Also, welcome to QuestionCove!! :D
:)
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