The quadrilateral shown is a rhombus. What is m ‹ 2?
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You have to know how the angles are related to each other
so angle 2 = 32\(^o\) as well and so does angle 4 and 5
to find angle 2, you can remember that the two adjacent angles add up to 180 so angles 1, 2, 4, and 5 add up to 180 and we know that angles 4 and 5 are 32 degrees so m<1 + m<2 + 32\(^o\) + 32\(^o\) = 180\(^o\) and remember that angle 1 and angle 2 are equal to each and they're also equal to angle 6 and 7 so if angle 2 is x degrees, then angle 1 is also x degrees so you have x + x + 32 + 32 = 180
solve for x, and you're all good to go
64
32+32
yes and subtract that on both sides then
180-64
good!
don't forget that x + x = 2x so now you have 2x = 180 - 64
58
Perfect! Well done :)
Thank u
You're most welcome :)
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