Question

maht number 2

Answer 1

@AZ

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilcutie2
@AZ
\(\color{#0cbb34}{\text{End of Quote}}\)
@az please help

Answer 3

@Angle

Answer 4

The area of a parallelogram = (base) x (height)

what is the height of the parallelogram in that picture?
(hint: heights will always make a right angle with the base)

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle
The area of a parallelogram = (base) x (height)

what is the height of the parallelogram in that picture?
(hint: heights will always make a right angle with the base)
\(\color{#0cbb34}{\text{End of Quote}}\)
12in

Answer 6

are we looking at the same picture?
where did you get 12 from?

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle
are we looking at the same picture?
where did you get 12 from?
\(\color{#0cbb34}{\text{End of Quote}}\)
7 in sorry

Answer 8

no... the height has to make a 90 degree angle with the base

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle
no... the height has to make a 90 degree angle with the base
\(\color{#0cbb34}{\text{End of Quote}}\)
they didn't add the 5

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilcutie2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle
no... the height has to make a 90 degree angle with the base
\(\color{#0cbb34}{\text{End of Quote}}\)
they didn't add the 5
\(\color{#0cbb34}{\text{End of Quote}}\)
@Angle

Answer 11

So what do you still need help with @lilcutie2?

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Timmyspu
So what do you still need help with @lilcutie2?
\(\color{#0cbb34}{\text{End of Quote}}\)
number 2

Answer 13

it's not that they "didn't add the 5"
but that they used 7 instead of 5