Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet?
welcome to qc and let me do some math
Thanks and ok
do you have answer choices?
Building A; it is around 16.35 feet taller than building B Building A; it is around 114.48 feet taller than building B Building B; it is around 16.35 feet taller than building A Building B; it is around 114.48 feet taller than building A
whitch 2 can you cross off?
Hey @DanielRichter let's first draw an image so we can solve this question
OK
|dw:1615917658346:dw|
Does that image make sense? (It's obviously not to scale) But we're looking at two buildings from an angle of 73 degrees Building A is 30 feet away Building B is 35 feet away we want to know how much taller the second building is from the first
So we need to first find the height of building A and then building B our answer will be height of building B minus height of building A do you know which trigonometric function we would need to use? we have the angle and we have the adjacent side we're trying to find the opposite side
Here's probably a better image
Tangent
Good! So let's first figure out the height of building A we're looking for the side opposite we know the angle is 73 and the adjacent side is 30 can you set it up to calculate the length of the opposite side? tan \(\theta\) = opposite/ adjacent
yes and it is 98.13
Perfect! Now calculate the length of building B the same way but remember, this time the adjacent side is 35! The angle stays the same at 73
114.48
Good! So that's the height of building B now they want to know which building is taller (obviously building B) and by how much so now you just calculate the difference 114.48 - 98.13 = ?
16.35
You got it!
thanks so much AZ
Of course, it was my pleasure!
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