Ask your own question, for FREE!
Mathematics 11 Online
rubypenaflor:

help

rubypenaflor:

@dude

dude:

For #17 This graph was flipped over the x axis So it would look different |dw:1616549355858:dw| The asymptote and domain should be the same but the y-intercept changes (Negative)

1 attachment
rubypenaflor:

so would it be C then?

dude:

Hmm not quite The asymptote and domain are the same, these two would be true We are looking for the false one So it's either A or B What is the y-intercept for this graph? \(-\frac13^0\)?

rubypenaflor:

A

dude:

Yes

rubypenaflor:

yayy

dude:

Now for #18 y-intercept is when they meet

1 attachment
rubypenaflor:

wouldnt it be 3/4?

dude:

No no, just look at where they meet

rubypenaflor:

oh my god its 1

dude:

Yes

rubypenaflor:

:0

dude:

For #19 we are translating the equation up Before we do that, we have to calculate the y-intercept and the asymptote of the current one Do you know what they are?

1 attachment
rubypenaflor:

the y intercept is 1

rubypenaflor:

and is the asymptote is -2?

dude:

Asymptote is not y=-2 Careful, its when the graph goes "straight"

rubypenaflor:

i think -3

rubypenaflor:

thats the first number that is going on the straight part

dude:

Hmm remember what we did in the previous ones It should be y=0

1 attachment
rubypenaflor:

ohh

dude:

Yes So we have a y-intercept at (0,1) and the asymptote at y=0 Now all we have to do is add 4 to the y-intercept and the asymptote

1 attachment
rubypenaflor:

so it would be either a or b then?

dude:

Right When you move up, you add only to the y-value \((0,1\color{green}{+4})=?\)

rubypenaflor:

it would be b

dude:

No, its the other way around \((0~~,~~1\color{green}{+4})=(0,5)\)

rubypenaflor:

ahh i see

rubypenaflor:

so then i feel like 20 would be D because that dont make sense

dude:

Perfect :)

rubypenaflor:

yessir

rubypenaflor:

okay i'm finished thank you so much for helping me i really appreciate it!

dude:

Of course! Good luck!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!