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Mathematics 5 Online
Aqual:

Factor By Grouping.

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@snowflake0531

Aqual:

x^6 + (x +1)

snowflake0531:

WHat

snowflake0531:

one sec, let me retype it

snowflake0531:

\[(x^3 +x^2) + (x + 1)\] First, what's the greatest common factor for \[x^3 and x^2\]

Aqual:

x

snowflake0531:

Er, are you sure?

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x^2

snowflake0531:

Yep So we have \[x^2 ( x+1) + 1(x+1)\] agreed?

Aqual:

whered the 1st x+1 come from?

snowflake0531:

Well, anything multiplied 1 is itself and to make the next step less confusing, I added a 1 in front

snowflake0531:

so yea? or no?

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yea

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i see now, it come from the x^2

snowflake0531:

wat

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cuz if it was 2x^2, itd be 2, but its 1x^2

snowflake0531:

._. No

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oh

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ok, im still confused

snowflake0531:

We had \[x^2 (x+1) + x+1\] do you get how we got that?

Aqual:

oh, yeah.

snowflake0531:

Okay and using the associative property or whatever it can also be written as \[x^2(x+1) + (x+1)\] yes?

Aqual:

ye

snowflake0531:

Okay, adn we look at the right half (x+1), do you agree that (x+1) equals 1(x+1) ?

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si

snowflake0531:

lol so now do you get how I got \[x^2(x+1) + 1(x+1)\]

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kinda

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im still confused where the 1 in x^2(x+1) came from

snowflake0531:

ohhhhh that 1

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ye

snowflake0531:

So, we got that the greatest common factor of \[x^3 + x^2\] is \[x^2\]

snowflake0531:

So, factor it out

Aqual:

i thought it would just be x

snowflake0531:

What do you get after you factor out \[x^2\] from \[x^3 +x^2\]

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but that would make it x^3 instead of x^2

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x

snowflake0531:

?

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well, x^2(x)

snowflake0531:

I have no clue what you're talking about lol but we would do this by \[(x^3+x^2)/x^2\] Which is \[\frac{ x^3 }{ x^2 } + \frac{ x^2 }{ x^2 }\]

snowflake0531:

What is \[\frac{ x^3 }{ x^2 }\]

snowflake0531:

Do you know the laws of exponents?

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hey, my dad came and helped

snowflake0531:

nice got the answer now?

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eh, nrly, im gonna ask my teach tmrw

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i gotta shower anyway

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and the wifi will be off by the time i get out.

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thank you tho, much appreciated.

snowflake0531:

kk

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