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Mathematics 19 Online
teressa24:

math problem screenshot down below

teressa24:

Florisalreadytaken:

the triangles are the same right? just their size if different?

teressa24:

yes

Florisalreadytaken:

then, we can use the rule of three

teressa24:

dont now the rule of three

Florisalreadytaken:

[\[12 ---> 3\] [\[20 ---> x\]

teressa24:

divide by 4?

Florisalreadytaken:

ehmm, no.

teressa24:

oh

Florisalreadytaken:

\[12 \times x = 20 \times 3\]

Florisalreadytaken:

divide both sides by 12 firstly

teressa24:

ok

Florisalreadytaken:

you winning right -- so we get \[x = (20 \times 3) / 12\]

teressa24:

60

Florisalreadytaken:

60/12=x

teressa24:

5

Florisalreadytaken:

good!

teressa24:

ok thank you

Shawnte:

All we need to do is scale down, we know taht side b goes down by a divicson of 3......so we need to scale down all sides by doing that

jhonyy9:

or with other name : use the proportionality of corresponding sides and write in this way \[\frac{ 12 }{ 3 } = \frac{ 20 }{ x } \] cross multiplie and calcule the x value

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