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Mathematics 14 Online
rxcklesskaisher:

Mr. Morris is going to save money and replace his sailboat's mainsail himself. He must determine the area of the mainsail in order to buy the correct amount of material. Calculate the area of the parallelogram to determine how much material should be purchased. Be sure to explain how to decompose this shape into rectangles and triangles. Describe their dimensions and show your work.

rxcklesskaisher:

1 attachment
Florisalreadytaken:

What is the formula for calculating the area of a parallelogram?

rxcklesskaisher:

bxlxw

Florisalreadytaken:

not the value formula

Florisalreadytaken:

volume*

Florisalreadytaken:

uhm, is there any image that goes with this?

rxcklesskaisher:

yes

rxcklesskaisher:

1 attachment
Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @rxcklesskaisher \(\color{#0cbb34}{\text{End of Quote}}\) not this uh

Shayla:

not this ?

Florisalreadytaken:

nope not that -- like an image of the type of mainsail

Florisalreadytaken:

|dw:1617048088444:dw|

Florisalreadytaken:

we can get many triangles, or just 2 triangles and the big rectangle

Florisalreadytaken:

as about the 1st part the formula would be \[a = B \times h\]

Florisalreadytaken:

we would need a diagram of the mainsail to determine the 2nd part bro

rxcklesskaisher:

thats the pic though

Florisalreadytaken:

its nonsense to me

Florisalreadytaken:

let's just find the area \[a = 20 \times 15\]

Florisalreadytaken:

\[a = 300 ft\]

Florisalreadytaken:

as for the second part, since we dont have a diagram, we will go with comparing the parallelogram with a rectangle with the same dimensions.

Florisalreadytaken:

we can see the superfluity triangles at the sides

rxcklesskaisher:

yes

Florisalreadytaken:

finding their dimension would be pretty easy

Florisalreadytaken:

|dw:1617049393982:dw|

Florisalreadytaken:

using the pythagoras theorem we would get \[? = 15^2+4^2\] \[? = \sqrt{225+16}\]

rxcklesskaisher:

im bad at to the square power

Florisalreadytaken:

calculators are not

rxcklesskaisher:

how i put it in the caculator?

Florisalreadytaken:

use google

Florisalreadytaken:

it will be prrox 15.5

Florisalreadytaken:

|dw:1617049842454:dw|

Florisalreadytaken:

thats about it 🤷‍♂️

rxcklesskaisher:

so 15.5 x??

Shayla:

Flor you've confused me

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken \[a = 300 ft\] \(\color{#0cbb34}{\text{End of Quote}}\) this will be our area

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @rxcklesskaisher so 15.5 x?? \(\color{#0cbb34}{\text{End of Quote}}\) that will be just the triangle's hypotenuse length

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Shayla Flor you've confused me \(\color{#0cbb34}{\text{End of Quote}}\) what? why?

rxcklesskaisher:

im so lost

Shayla:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken \(\color{#0cbb34}{\text{Originally Posted by}}\) @Shayla Flor you've confused me \(\color{#0cbb34}{\text{End of Quote}}\) what? why? \(\color{#0cbb34}{\text{End of Quote}}\) I dont know the way you did it was just so confusing

Florisalreadytaken:

its not even complicated... what is confusing about it?

Shayla:

i dont know im just confused

Florisalreadytaken:

It's no surprise why youre failing at math

rxcklesskaisher:

im kinda failing

Shayla:

I am failing but its not my fault meanie

Florisalreadytaken:

it is not? how come

rxcklesskaisher:

u dont think so?

Shayla:

I spend most of my time talking to you rather than doing hw 😌

rxcklesskaisher:

all i need is helpp

Florisalreadytaken:

so did i -- thats not an excuse

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @rxcklesskaisher all i need is helpp \(\color{#0cbb34}{\text{End of Quote}}\) didnt you get your answers already? and oh, make sure to send your teacher a diagram of the parallelogram

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken Created with Raphaël2020154415??15.5== 15.5Reply Using Drawing \(\color{#0cbb34}{\text{End of Quote}}\) .

rxcklesskaisher:

a==300ft?

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @rxcklesskaisher a==300ft? \(\color{#0cbb34}{\text{End of Quote}}\) yes

rxcklesskaisher:

how im going to show my work

rxcklesskaisher:

like bruh

Florisalreadytaken:

just show the steps of the equations

rxcklesskaisher:

imma jus get a zero

Florisalreadytaken:

you have your answer just in front of you, and you decide to get a 0? wise

rxcklesskaisher:

2 much to explain

Shayla:

Okay so you see how flor divided the parallelogram into two triangles and a rectangle right ?

Shayla:

Now the rectangle itself would be 16*15 whereas the triangles would be together 15*4

Shayla:

15*16=240 15*4=60

Shayla:

add them together to get 300

Shayla:

Okay does that make sense ?

rxcklesskaisher:

yes thank you

Shayla:

Ofc!

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