Question

math problem

Answer 1

@Florisalreadytaken

Answer 2

@Laylalyssa

Answer 3

@snowflake0531

Answer 4

Do you know the vertex form of a quadratic equation?

y = (x-h)^2 + k

where (h, k) is the vertex

What is the vertex in your image?

Answer 5

-3, 4

Answer 6

Good, so h is -3 and k is 4

so

y = (x - (-3))^2 + 4

x - (-3) is the same thing as x+3

So we get

y = (x+3)^2 + 4

Can you expand that? What is (x+3)^2 = ?

Answer 7

Remember the formula
\( (a+b)^2 = a^2 + 2ab + b^2\)

Answer 8

x^2 + 6x + 9

Answer 9

Good so now we have

y = (x+3)^2 + 4

y = x^2 + 6x + 9 + 4

Just simplify by adding the like terms. What is 9 + 4 = ?

Answer 10

13

Answer 11

And so what's your final answer?

Answer 12

Where did you get the 2 from?

Answer 13

i leave it blank?

Answer 14

remember that \( x^2 \) is the same thing as \( 1 x^2\)

when they don't write any number in front of it, that means it's `1`

Answer 15

That's correct

Answer 16

wait

Answer 17

the quadratic function is flipped

Answer 18

lol

Answer 19

so we have

y = a(x-h)^2 + k

and we said that (h, k) is (-3, 4)

and we need to figure out what 'a' is

y = a(x + 3)^2 + 4

Answer 20

If you look at the graph, you can see there's a point (-2, 2) on the line

so we can use that to find the value of 'a' and then we distribute just like we did earlier

2 = a(-2+3)^2 + 4

what is a = ?

Answer 21

im not sure but i have a new uestion

Answer 22

Sure, post it