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Mathematics 9 Online
bri05:

i need help with numbers 5-10 please show work to

bri05:

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BabydollBlake:

is this pentagram theorem?

bri05:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @BabydollBlake is this pentagram theorem? \(\color{#0cbb34}{\text{End of Quote}}\) i dont think so

BabydollBlake:

hmm

bri05:

could u help me?

BabydollBlake:

Ill try, im trying to figure out how to do it

BabydollBlake:

You don't have a formula??

bri05:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @BabydollBlake You don't have a formula?? \(\color{#0cbb34}{\text{End of Quote}}\) not rlly im rlly lost

BabydollBlake:

Crap, I wanna help, but cant seem to understand it

bri05:

its ok ig

BabydollBlake:

@jhonyy9

BabydollBlake:

Mods act like they cant ever see anyone @ing them.

bri05:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @BabydollBlake Mods act like they cant ever see anyone @ing them. \(\color{#0cbb34}{\text{End of Quote}}\) true

snowflake0531:

These are problems use the pythagorean theorem and a few trig functions Do you know what the pythagorean theorem is, and what sin, cos, tan are?

bri05:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 These are problems use the pythagorean theorem and a few trig functions Do you know what the pythagorean theorem is, and what sin, cos, tan are? \(\color{#0cbb34}{\text{End of Quote}}\) yes yes yes and yes

snowflake0531:

kk, and btw, you don't need to quote me lol

snowflake0531:

So let's first look at number 5 Because this is a square, all sides are equal So we find AX using the pythagorean theorem with sides AW and WX Can you tell me how long AW and WX are?

bri05:

wouldnt the answer be 1 for how long they are?

snowflake0531:

...AZ is 1, which means AW is how long?

bri05:

1 to the square root of 2?

snowflake0531:

.... WZ=XY, so WZ is 4 But AZ is 1, which means AW is how long

bri05:

idkkk i rlly dont know

snowflake0531:

... When a segment is 4 units long... but one part is 1... so how long is left of it... simple subtraction e.e

bri05:

oh my im dumb its 3

snowflake0531:

yee, so it's 3 So now that we have one leg is that is 3 units long, one side that is 4 units long, what is the hypotenuse? (remember that this is a right triangle)

bri05:

its 5 right becuase its a triple

snowflake0531:

Yep so number 5 is 5

snowflake0531:

And then we look at number 6 Use the pythagorean theorem

bri05:

ok ok

bri05:

ohhh so with number 6 you just have to write out the probelm with number 8 in the c squared part right?

snowflake0531:

...what? lol

bri05:

sry nvm i think i got number 6 but i dont understand 7

snowflake0531:

Do you know your 45 45 90 triangles?

bri05:

yea i do

snowflake0531:

So, 1, 1, sqrt2 If 6sqrt2 was 1, multiply 6sqrt2 with sqrt2, what do you get

bri05:

wha-

snowflake0531:

1, 1, sqrt2 6sqrt2, 6 sqrt2, __

snowflake0531:

So what is \[6(\sqrt2)(\sqrt2)\]

snowflake0531:

Hint that sqrtx times sqrtx equals x

bri05:

i got 12

snowflake0531:

yep

snowflake0531:

For number 8, do you remember 30, 60, 90 degree triangles?

bri05:

yea i do

snowflake0531:

so do you know how to find x adn y

bri05:

not rlly

snowflake0531:

You know these sides, and so, put it into the actual triangle, compare and multiply

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snowflake0531:

sqrt3 = 36 \[\sqrt3(12\sqrt3)=36\]

snowflake0531:

And this is like scaling, so multiply the sides by 12 sqrt3

bri05:

ohh so the answer for x would be 12sqrt3?

snowflake0531:

yep and y would be that times 2

bri05:

wait wha-

snowflake0531:

Because y is 2x, as seen in the ^^^ image

bri05:

okkk then how would i find y?

snowflake0531:

2 times x

bri05:

im lost on how to do that sry

snowflake0531:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @bri05 im lost on how to do that sry \(\color{#0cbb34}{\text{End of Quote}}\) You know that x is 12 sqrt 3 So y=2x So what is 2(12sqrt3)?

bri05:

i got a decimal of 41.56

snowflake0531:

....Don't do it in decimal... keep it in square root form \[2(12\sqrt3)\]

bri05:

i did that and got a decimal ;-;

snowflake0531:

keep it in square root form... what is 12 times 2

snowflake0531:

Wait, btw, do you know how to multiply square root stuffs?

bri05:

no i dont

snowflake0531:

When one is an integer, another a square root, multiply the integers together, in this case, 2 times 12, and then add the sqrt3 behind

bri05:

i still get a decimal what am i doing wrong?

snowflake0531:

.... don't use a frickin calculator.... what did i just tell you...

snowflake0531:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 When one is an integer, another a square root, multiply the integers together, in this case, 2 times 12, and then add the sqrt3 behind \(\color{#0cbb34}{\text{End of Quote}}\)

bri05:

oh my gosh i so fing dumb

snowflake0531:

I want an answer, not a 'i'm so dumb'

snowflake0531:

What is 2 times 12

bri05:

24

snowflake0531:

so it's 24 sqrt3

bri05:

oh my ok

bri05:

ok what abt number 9

snowflake0531:

So for number 9, it's the 45 45 90 degree triangle thing again what do youg et

bri05:

so we have 10 sqrt2 what would i told then?

snowflake0531:

1, 1, sqrt2 WHat other side is equal to 10 sqrt2

bri05:

y is

bri05:

so would y be 10?

snowflake0531:

.... y would be \[10\sqrt2(\sqrt2)\]

bri05:

y is 20

snowflake0531:

yes

bri05:

ok then what would x be?

snowflake0531:

.... 1, 1, sqrt2

bri05:

X is also 10sqrt2 isnt it?

snowflake0531:

yep

snowflake0531:

For 10, we have 30 60 90 again, but this one's easier, since we start with the hypotenuse side

bri05:

okkkkk...

snowflake0531:

So what do you get for x, remember that it is half the value of the hypotenuse

bri05:

10.5 is x right

snowflake0531:

Yes and y is sqrt 3 times x so what is it Remember, not calculator.... Just... multiply the values

bri05:

sooo y is 10.5sqrt3?

snowflake0531:

yep

bri05:

thxs i might have more

snowflake0531:

e.e okay lol

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