i need help with numbers 5-10 please show work to
is this pentagram theorem?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @BabydollBlake is this pentagram theorem? \(\color{#0cbb34}{\text{End of Quote}}\) i dont think so
hmm
could u help me?
Ill try, im trying to figure out how to do it
You don't have a formula??
\(\color{#0cbb34}{\text{Originally Posted by}}\) @BabydollBlake You don't have a formula?? \(\color{#0cbb34}{\text{End of Quote}}\) not rlly im rlly lost
Crap, I wanna help, but cant seem to understand it
its ok ig
@jhonyy9
Mods act like they cant ever see anyone @ing them.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @BabydollBlake Mods act like they cant ever see anyone @ing them. \(\color{#0cbb34}{\text{End of Quote}}\) true
These are problems use the pythagorean theorem and a few trig functions Do you know what the pythagorean theorem is, and what sin, cos, tan are?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 These are problems use the pythagorean theorem and a few trig functions Do you know what the pythagorean theorem is, and what sin, cos, tan are? \(\color{#0cbb34}{\text{End of Quote}}\) yes yes yes and yes
kk, and btw, you don't need to quote me lol
So let's first look at number 5 Because this is a square, all sides are equal So we find AX using the pythagorean theorem with sides AW and WX Can you tell me how long AW and WX are?
wouldnt the answer be 1 for how long they are?
...AZ is 1, which means AW is how long?
1 to the square root of 2?
.... WZ=XY, so WZ is 4 But AZ is 1, which means AW is how long
idkkk i rlly dont know
... When a segment is 4 units long... but one part is 1... so how long is left of it... simple subtraction e.e
oh my im dumb its 3
yee, so it's 3 So now that we have one leg is that is 3 units long, one side that is 4 units long, what is the hypotenuse? (remember that this is a right triangle)
its 5 right becuase its a triple
Yep so number 5 is 5
And then we look at number 6 Use the pythagorean theorem
ok ok
ohhh so with number 6 you just have to write out the probelm with number 8 in the c squared part right?
...what? lol
sry nvm i think i got number 6 but i dont understand 7
Do you know your 45 45 90 triangles?
yea i do
So, 1, 1, sqrt2 If 6sqrt2 was 1, multiply 6sqrt2 with sqrt2, what do you get
wha-
1, 1, sqrt2 6sqrt2, 6 sqrt2, __
So what is \[6(\sqrt2)(\sqrt2)\]
Hint that sqrtx times sqrtx equals x
i got 12
yep
For number 8, do you remember 30, 60, 90 degree triangles?
yea i do
so do you know how to find x adn y
not rlly
You know these sides, and so, put it into the actual triangle, compare and multiply
sqrt3 = 36 \[\sqrt3(12\sqrt3)=36\]
And this is like scaling, so multiply the sides by 12 sqrt3
ohh so the answer for x would be 12sqrt3?
yep and y would be that times 2
wait wha-
Because y is 2x, as seen in the ^^^ image
okkk then how would i find y?
2 times x
im lost on how to do that sry
\(\color{#0cbb34}{\text{Originally Posted by}}\) @bri05 im lost on how to do that sry \(\color{#0cbb34}{\text{End of Quote}}\) You know that x is 12 sqrt 3 So y=2x So what is 2(12sqrt3)?
i got a decimal of 41.56
....Don't do it in decimal... keep it in square root form \[2(12\sqrt3)\]
i did that and got a decimal ;-;
keep it in square root form... what is 12 times 2
Wait, btw, do you know how to multiply square root stuffs?
no i dont
When one is an integer, another a square root, multiply the integers together, in this case, 2 times 12, and then add the sqrt3 behind
i still get a decimal what am i doing wrong?
.... don't use a frickin calculator.... what did i just tell you...
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 When one is an integer, another a square root, multiply the integers together, in this case, 2 times 12, and then add the sqrt3 behind \(\color{#0cbb34}{\text{End of Quote}}\)
oh my gosh i so fing dumb
I want an answer, not a 'i'm so dumb'
What is 2 times 12
24
so it's 24 sqrt3
oh my ok
ok what abt number 9
So for number 9, it's the 45 45 90 degree triangle thing again what do youg et
so we have 10 sqrt2 what would i told then?
1, 1, sqrt2 WHat other side is equal to 10 sqrt2
y is
so would y be 10?
.... y would be \[10\sqrt2(\sqrt2)\]
y is 20
yes
ok then what would x be?
.... 1, 1, sqrt2
X is also 10sqrt2 isnt it?
yep
For 10, we have 30 60 90 again, but this one's easier, since we start with the hypotenuse side
okkkkk...
So what do you get for x, remember that it is half the value of the hypotenuse
10.5 is x right
Yes and y is sqrt 3 times x so what is it Remember, not calculator.... Just... multiply the values
sooo y is 10.5sqrt3?
yep
thxs i might have more
e.e okay lol
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