Question

I need help with these two o:

Answer 1

Use the pythagorean theorem like you did earlier

Remember that

\( (\sqrt{x})^2 = x\)

if you square a square root, you're just left with whatever was inside the square root

Answer 2

So inside the square root would be 10? for the equation with n.

Answer 3

yeah

so
a^2 + b^2 = c^2

and
put in those values

\( (\sqrt{10})^2 + n^2 = 10^2\)

solve for n

Answer 4

Okay so..

10^2 + n^2 =10^2
100 +n^2 = 100
100-100=0 100-100=0

So.. the answer would be Zero?

Answer 5

No it's sqrtx^2 which means that it's x

So it's 10 + n^2 = 100

Answer 6

Ohh so it'd be 90?

Answer 7

no

10 + n^2 = 100

subtract 10 on both sides

n^2 = ??

remember, we're solving for 'n'

Answer 8

10-10=0
10-100=90 ._.

I'm confused now.

Answer 9

100 - 10 = 90 **

10 + n^2 = 100

10 + n^2 - 10 = 100 - 10

n^2 = 90

does that make sense so far?

Answer 10

Yeah..

Answer 11

So then how do you get n all by itself?

we have to take the square root of it

Answer 12

\[\sqrt{90}\]


and I've gtg o: I'll be on tomorrow.

Answer 13

You got it!

And we could simplify that a little more

but essentially that's the same concept you apply to the other question

Answer 14

I'll see you tomorrow then :)