Question

math problem

Answer 1

y varies jointly with x means y and x are in the form y = kx

Answer 2

y varies with the square of z means y and z are in the form of y = kx^2
btw k here is just any integer

Answer 3

so here, putting it together, we get y = kx*kz^2
however, remember that with constants, k^2 = another integer, so really we can just still set the constant to k
so our equation is y = kxz^2

Answer 4

now we plug in y = 90, x =5, and z=3
90 = k*5*3^2 = k*45
2 = k

Answer 5

so our equation is
y = 2xz^2

Answer 6

@Florisalreadytaken

Answer 7

i think @minustempo did a great job on that and explained it pretty well -- why did you tag me then? -- you stuck?

Answer 8

i just needed to kno if their right

Answer 9

ah ok -- yeah it's right!

Answer 10

if it detects it as a wrong answer, then just plug in the numbers for x, y, and z