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@Florisalreadytaken
@snowflake0531
help
we did a similar to this just now! this is what they have stated \[ y \propto x^3 \] We must convert that, into an equation by adding the constant of variation (k). \[ y=k \times x^3 = kx^3 \]
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8/4 ?
8/4^2?
\( k= \frac{8} { 4^3} \) it is cubed, not squared
0.125
yupp so: \[ y=0.125x^3 \]
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the ansers 0.125x^3
your teacher is asking for the equation, not just the answer -- thats why it would be \(y=0.125x^3 \)
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