Question

Find the tangent of ∠V.

Answer 1

I know what tan is

Answer 2

Tan= opp/ adj

Answer 3

Exactly, so tan V is going to be the side opposite / adjacent

but first we have to calculate that opposite side

since we have a right triangle, use Pythagorean theorem to solve for that side

a^2 + b^2 = c^2

Answer 4

Ok

Answer 5

8^2+29^2

Answer 6

no

8 is your HYPOTENUSE which would be 'c'

a and b are the two legs of the triangle

Answer 7

So a^2+29^2=8^2

Answer 8

be careful, it's not 29. It's square root of 29 or \(\sqrt{29}\)

Answer 9

and you should know this:

\((\sqrt{x})^2 = x\)

if you try to square a square root, they basically cancel out

Answer 10

Ok

Answer 11

so

\( (\sqrt{29})^2 + x^2 = 8^2\)

can you solve for x?

Answer 12

29*29

Answer 13

29*29

Answer 14

no

what is \( (\sqrt{29})^2 = \)

Answer 15

and what is 8^2 = ?

Answer 16

The first one is 156

Answer 17

Second one is 64

Answer 18

No

remember, it's SQUARE ROOT of 29

if we square the square root, we'll only be left with 29

so now we have

29 + x^2 = 64

can you solve for x?

Answer 19

64-29

Answer 20

yes

what is that?

and remember to take the square root on both sides after that

Answer 21

58.1

Answer 22

do you have a calculator??

Answer 23

Nah

Answer 24

Do you have access to the internet???

https://www.google.com/search?q=64-29

Answer 25

so if

x^2 = 64 - 29

then x is going to be sqrt(64-29)

does that make sense??

so what is 64 - 29 = ??

Answer 26

35

Answer 27

so that means that the side is sqrt(35)

so we now have



so what is tan V = ?

Answer 28

8/29

Answer 29

What side is OPPOSITE the angle V?

and what side is ADJACENT??

Answer 30

also I don't know how many times I have to tell you

but it is \(\Huge \text{NOT 29}\)

It's \(\Large \sqrt{29}\)

The same thing goes for 35, it's \(\Large \sqrt{35}\)

Answer 31

So confused

Answer 32

What are you confused about?

Have you not learned about square roots?