Look at the figure:

An image of a right triangle is shown with an angle labeled x. If tan x° = 6 divided by g and sin x° = 6 divided by h, what is the value of cos x°?

cos x° = h divided by g
cos x° = g divided by h
cos x° = gh
cos x° = 6g

Question

Look at the figure:

An image of a right triangle is shown with an angle labeled x. If tan x° = 6 divided by g and sin x° = 6 divided by h, what is the value of cos x°?

cos x° = h divided by g
 cos x° = g divided by h
 cos x° = gh
 cos x° = 6g

nettym · Answer

Can you provide a picture of the figure? "An image of a right triangle "

kekeman · Answer

nettym · Answer

ty, so any ideas on what the correct answer is?

kekeman · Answer

Well i guessed Cosine=g/h, or g divided by h

Creed · Answer

Correct, Kekeman. It is Cosine=g/h!
Nice work!

Florisalreadytaken · Answer

what? how is that correct?😂🤣

nettym · Answer

@Florisalreadytaken 
wouldnt it be cos x = gh ?

Florisalreadytaken · Answer

thats correct!

because, what we're given is:$$ \tan \; x^o   = \frac{6 }{g} $$
and

$$ sin \; x^o =  \frac{6 }{h}$$
we know that $ \tan x^o= \frac{\sin^o }{\cos^o}  $

thus:
$$ \frac{6 }{g} = \frac{ \frac{6 }{h } } {\cos \; x^o}     $$

bu doing the math, we get $ cos \; x^o = gh  $

Florisalreadytaken · Answer

by^*

nettym · Answer

Ohhh so i was correct, ty :c

Florisalreadytaken · Answer

@kekeman change your answer lol!

kekeman · Answer

The correct answer was  cos x° = g divided by h

Florisalreadytaken · Answer

oh i see, that was right! i did it the way around haha! good catch.