Question

math problem

Answer 1

@florisalreadytaken

Answer 2

dint you just do 1 same graph just now? look at the other post, and i will just correct the answer for you.

Answer 3

its not the same @florisalreadytaken

Answer 4

The numbers might not be the same... but the idea is the same

\(y = a(b^x)\)

when x = 0, y = -3
when x = 1, y = -6
when x = 2, y = -12

plug in x = 0 and y = -3

you can find the value of 'a'

and then once you know 'a', plug in x= 1 and y = -6, and you'll find the value of b

Answer 5

a(-6)

Answer 6

I have no idea what that means but no

Answer 7

\(-3 = a(b^0)\)

what is b^0 = ?

Answer 8

anything to the power of 0 equals...

Answer 9

0

Answer 10

no, it equals 1

anything to the power of 0 equals 1

Answer 11

-6

Answer 12

??

-3 = a * 1

what is a?

Answer 13

-3

Answer 14

good, so now that you know 'a'

you can find 'b'

\(\Large y = -3(b^x)\)

so when x = 1, then y = -6

\(\Large -6 = -3(b^1)\)

anything to the power of 1 is going to be that same number

so like for example
5^1 = 5
100^1 = 100

so b^1 = b

can you solve for b now?

Answer 15

-3(2)

Answer 16

There you go

just don't forget to write the ^x as well

Answer 17

Yup