3.
(05.01 LC)
Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.

The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points)

By distribution, AC2 plus AB2 = BC multiplied by the quantity DC plus AB.
By distribution, AC2 plus AB2 = BC multiplied by the quantity DC plus BD.
By distribution, AC2 plus AD2 = BC multiplied by the quantity DC plus AB.
By distribution, AC2 plus AD2 = BC multiplied by the quantity DC plus BD.

Question

3. 
(05.01 LC)
Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.

The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points)

By distribution, AC2 plus AB2 = BC multiplied by the quantity DC plus AB.
By distribution, AC2 plus AB2 = BC multiplied by the quantity DC plus BD.
By distribution, AC2 plus AD2 = BC multiplied by the quantity DC plus AB.
By distribution, AC2 plus AD2 = BC multiplied by the quantity DC plus BD.

jhonyy9 · Answer

|dw:1619593486545:dw|

this my posted image hope will help you understanding more easy

and to prove

$BC^2 = AB^2 + AC^2$

surjithayer · Answer

$$BC^2=BC \times BC=BC \times (BD+DC)$$