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Mathematics 17 Online
pytdestiny:

The cost of producing transistors decreases by 20% every year. If it currently costs $490 to produce a billion transistors, how much will it cost to produce a billion transistors in 7 years? If necessary, round your answer to the nearest cent.

Extrinix:

so to figure this out, figure out what 20% of 490 is, \(\color{tomato}{490} \times \color{violet}{0.20} = \color{cyan}{x}\) then take the answer for x and add it into this equation \(\color{tomato}{490}-\color{lime}{7}(\color{cyan}{x})=\color{yellow}{c}\) find c (cost) and that should be your answer.

pytdestiny:

20% of 490 = 98

Extrinix:

correct, now input that in for x

pytdestiny:

47334?

Extrinix:

how did you get that answer?

pytdestiny:

oh I think I did something wrong. I did 490-7 and then times that by 98

Extrinix:

no, you did the math correctly

Extrinix:

oh, I see where you got your answer.

pytdestiny:

would it be correct

Extrinix:

oh, we need to do conversions

Extrinix:

Wait wait wait, this question would be in the negatives due to the fact that if it decreased 20% out of 490 in 7 years, that would mean the price doesn't exist.

Extrinix:

Ok, so i believe your question is incorrect, it should be `increases` not `decreases`, or else it would be negative spending

pytdestiny:

are you sure?

pytdestiny:

this is an official website

pytdestiny:

@snowflake0531

snowflake0531:

\[480(0.8)^7\]

snowflake0531:

shoot *490

snowflake0531:

490 as the principal amount, 0.8 because 1-0.2, adn 7 bc 7 years

pytdestiny:

= 102.760448

snowflake0531:

yes so 102.76

pytdestiny:

can you help with a few more please?

snowflake0531:

In decrease, just use principal amount times (1-(decrease rate) to the power of time/year \[P(1-r)^t\]

pytdestiny:

can you help with more

snowflake0531:

sure-, i guess

pytdestiny:

The half-life of a radioactive kind of nickel is 96 years. How much will be left after 192 years, if you start with 1,040 grams of it?

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