An observer (O) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of elevation from his line of sight. How high is the kite flying over the building? You must show all work and calculations to receive full credit.

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lemon1boy1 · Answer

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snowflake0531 · Answer

This question is asked weirdly "How high is the kite flying over the building?" you mean above the ground? o-O

well, despite that, let's just find h
sin(x) = opposite/hypotenuse
cos(x) = adjacent/hypotenuse
tan(x) = opposite/adjacent

In this case we want to find opposite adn have adjacent so we do

$$ tan( 29 ) = \frac {h} {400} $$

snowflake0531 · Answer

ANd so by this we have
$$h = 400tan(29) $$

lemon1boy1 · Answer

@snowflake0531 wrote:

This question is asked weirdly "How high is the kite flying over the building?" you mean above the ground? o-O well, despite that, let's just find h sin(x) = opposite/hypotenuse cos(x) = adjacent/hypotenuse tan(x) = opposite/adjacent In this case we want to find opposite adn have adjacent so we do $$ tan( 29 ) = \frac {h} {400} $$

yeah I think they mean over the ground

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