The diagonal of a rectangle measures 13 meters, what is the area of the rectangle if its length is 7 meters more than its width? What is the area of each triangle formed? Draw the figure
Can you draw the figure? We have a rectangle. The diagonal is 13 If we call the width 'x' Then the length is 7 more than the width which means it's 7 + x Remember that the area of a rectangle is equal to length * width And the area of a triangle is equal to 1/2 * base of the triangle * height or in this case 1/2 * length * width (since the width is the height and the length is the base of the triangle) |dw:1620517289263:dw|
We also have to use the Pythagorean theorem to calculate the width and length |dw:1620517634540:dw| We're going to get a quadratic that we have to solve when you plug in x, x+7, and 13 in as `a`, `b`, and `c` respectively
Then once you know the width and length, you can find the area of the rectangle and triangle using the formulas I told you earlier
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