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Mathematics 15 Online
imyoursgirlsgirl:

math help

imyoursgirlsgirl:

imyoursgirlsgirl:

@AZ

Imagine:

What is the math lesson about?

imyoursgirlsgirl:

find segment lengths in circles

new2luv:

do you have to find the degree of the letters

imyoursgirlsgirl:

it says find PQ

new2luv:

https://youtu.be/iEjFQT97LAI hope this helps

imyoursgirlsgirl:

ive already watched videos

AZ:

Same formula as last time |dw:1620654779561:dw|

AZ:

so for your question 'a' is 12 'b' is 6 and 'c' is your 'x'

imyoursgirlsgirl:

so 12^2=6(6+x)

Imagine:

\[(12)(12)=(6)(6+x)\] Mutiply as needed. \[144=36+6x\] Subtract the 36. \[108=6x\] Do 108/6=? \[x=?\]

AZ:

@imyoursgirlsgirl wrote:
so 12^2=6(6+x)
yup

imyoursgirlsgirl:

ok so i first time 6 with everything in the ( )

AZ:

you got it

imyoursgirlsgirl:

ok so 6*6 is 36 and 6*x.. would it be just 6x

Imagine:

I showed the work if you'd like... Up there.

Imagine:

@imagine wrote:
\[(12)(12)=(6)(6+x)\] Mutiply as needed. \[144=36+6x\] Subtract the 36. \[108=6x\] Do 108/6=? \[x=?\]

imyoursgirlsgirl:

x=18

imyoursgirlsgirl:

thanks AZ and imagine

AZ:

@imyoursgirlsgirl wrote:
ok so 6*6 is 36 and 6*x.. would it be just 6x
yup yup and if you see what Imagine showed, you just subtract 36 on both sides and then you divide by 6

AZ:

@imyoursgirlsgirl wrote:
x=18
so good job :)

imyoursgirlsgirl:

<3

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