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@AZ
What is the math lesson about?
find segment lengths in circles
do you have to find the degree of the letters
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it says find PQ
ive already watched videos
Same formula as last time |dw:1620654779561:dw|
so for your question 'a' is 12 'b' is 6 and 'c' is your 'x'
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so 12^2=6(6+x)
\[(12)(12)=(6)(6+x)\] Mutiply as needed. \[144=36+6x\] Subtract the 36. \[108=6x\] Do 108/6=? \[x=?\]
@imyoursgirlsgirl wrote:
so 12^2=6(6+x)
ok so i first time 6 with everything in the ( )
you got it
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ok so 6*6 is 36 and 6*x.. would it be just 6x
I showed the work if you'd like... Up there.
@imagine wrote:
\[(12)(12)=(6)(6+x)\]
Mutiply as needed.
\[144=36+6x\]
Subtract the 36.
\[108=6x\]
Do 108/6=?
\[x=?\]
x=18
thanks AZ and imagine
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@imyoursgirlsgirl wrote:
ok so 6*6 is 36 and 6*x.. would it be just 6x
@imyoursgirlsgirl wrote:
x=18
<3
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