A line whose slope is 4 and passes through the point (0, -9) lies on the line whose equation is: A. 4x + y = -9 B. 4x - y = 9 C. y - 4x = 9
y = mx + b m is the slope b is the y-intercept so replace 'm' with 4 and then to solve for 'b', plug in the point (0, -9) That's in the form of (x, y) so replace x with 0 and y with -9 and then solve for b
can I have the equation so its clear for me
Let's do it, step by step The slope-intercept form for an equation is this y = mx + b they told you the slope is 4 replace 'm' with 4 what do you get so far when you replace 'm' with 4
\[y= 4x+b \]
Good now they told you this line passes through the point (0, -9) points are written in the form of (x, y) so replace x with 0 and y with -9 what do you get then?
\[-9=40+b\]
that wat i about said
no, 4x means 4 * x so 4 * 0 -9 = (4 * 0) + b
what is 4 * 0 = ? and then can you solve for b?
ohh ok
0 right?
yes, 4 * 0 = 0 so we have -9 = 0 + b so what is b?
maybe y? i dont know
uhh no? anything plus 0 is going to be that number so b is -9
so we have y = mx + b where m is 4 and we just found that 'b' is -9 we have y = 4x - 9 can you re-arrange this equation and see which of the answer choices it would match up to?
Hint: subtract y on both sides and then add 9 on both sides
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