If I use distributive property to solve this problem how would I do it? 1(2x+4) -2+2=10
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Spectrum:
We just started learning this and I just be sitting in the back of class staring like 0-0
Extrinix:
Ok, so first off do you know what you have to do first?
kittybasil:
Rewording:\[1(2x+4)-2+2=10\]Firstly, you can see that two numbers cancel out:\[1(2x+4)\cancel{\color{red}{-2+2}}=10\]\[\therefore1(2x+4)=10\]Now we apply the distributive property, which is \(a(b+c)=a(b)+a(c)\). Based on that, what should the next step be?
Extrinix:
Annnd I got canceled out... as usual...
kittybasil:
kittybasil wrote:
Rewording:\[1(2x+4)-2+2=10\]Firstly, you can see that two numbers cancel out:\[1(2x+4)\cancel{\color{red}{-2+2}}=10\]\[\therefore1(2x+4)=10\]Now we apply the distributive property, which is \(a(b+c)=a(b)+a(c)\). Based on that, what should the next step be?
Hint: \(b=2x\)
I know, usually when you start working with the Distributive property each placeholder variable is a single-digit term, but now we're going with algebraic expressions and variable unknowns.
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kittybasil:
extrinix wrote:
Annnd I got canceled out... as usual...
nah, you've got a medal from OP. I'm just here as the tip machine. π
kittybasil:
I don't want that medal so don't throw it this way! runs away quickly
Spectrum:
So 2x+4=10
Spectrum:
subtract 4 from both sides, 2x=6
kittybasil:
Correct! You're doing great π
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Spectrum:
divide both sides by 2 and x=3
Spectrum:
thenkyou extrinix and basil
Extrinix:
No need to thank me...
kittybasil:
Absolutely thank him. He was here first.
Also I go by Kitt haha
kittybasil:
Good luck on your studies! β
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kittybasil:
extrinix wrote:
I'm going to swap your name around a bit, Bay.
No pls. I only go by my full user or Kitt. π
Spectrum:
Thenkyou! β€οΈπ’ no need to make this post off-topic. so plez dontβ€οΈβ€οΈ
kittybasil:
It's okay. Just clarifying what people should use to refer to me is all. π