Question

2x2-13x+7=x2
Round to the nearest tenth

Answer 1

choose one, graphing or quadratic formula

Answer 2

quadratic formula

Answer 3

like a first step subtract from both sides x^2

Answer 4

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\\ax^2+bx+c\\x^2-13x\]

Answer 5

-13x+7 *
plug it in, and do it

Answer 6

Alr ty

Answer 7

@salttheloser step by step please and explain it

Answer 8

@trash do you get how to do it by yourself?

Answer 9

Yezzir thank yall<3

Answer 10

\[2x^2-13x+7=x^2\]
or \[x^2-13x+7=0\]
either solve by completing squares or by using quadratic formula
\[x^2-13x+(-\frac{ 13 }{ 2 })^2=-7+(-\frac{ 13 }{ 2 })^2\]
\[(x-\frac{ 13 }{ 2 })^2=-7+\frac{ 169 }{ 4 }=\frac{ -28+169 }{ 4 }=\frac{ 141 }{ 4 }\]
\[x=\frac{ 13 }{2 }\pm \frac{ \sqrt{141} }{ 2 }\]
\[either~x=\frac{ 13+\sqrt{141} }{ 2 }\approx 12.44\]
\[or~x=\frac{ 13-\sqrt{141} }{ 2 }\approx 0.56\]