A rectangle’s length is three times its width, w. Its area is 243 square units. Which equation can be used to find the width of the rectangle?

w2 = 3(243)
3w2 = 243
4w2 = 243
3w2 = 3(243)

Question

A rectangle’s length is three times its width, w. Its area is 243 square units. Which equation can be used to find the width of the rectangle?

w2 = 3(243)
3w2 = 243
4w2 = 243
3w2 = 3(243)

GoodFellow · Answer

quickly draw a figure of that rectangle & mark the said dimensions & try to write for area

GoodFellow · Answer

drawing a figure, solves a question 50%,

Florisalreadytaken · Answer

1) drawing a figure for it is just pointless.
2) where the literal Pear did alex get those numbers from?

GoodFellow · Answer

@florisalreadytaken wrote:

1) drawing a figure for it is just pointless. 2) where the literal Pear did alex get those numbers from?

not pointless, it helps him at his level

GoodFellow · Answer

at my level its just calculations by mind

Alex1513 · Answer

sorry mix up

Alex1513 · Answer

Width = w

Length = 3w

Area = 243 square units

length *width = 243

3w * w = 243

Florisalreadytaken · Answer

"A rectangle’s `length is three times its width`, w. Its `area is 243` square units. Which equation can be used to find the width of the rectangle?"

having that info we can write:
$$\color{lightskyblue}{w \times 3w}= 243 sq.^2$$
$$  \color{lightskyblue}{3w^2} =243 sq.^2  $$
which option is that?

DogGirl27 · Answer

@florisalreadytaken wrote:

"A rectangle’s `length is three times its width`, w. Its `area is 243` square units. Which equation can be used to find the width of the rectangle?" having that info we can write: $$\color{lightskyblue}{w \times 3w}= 243 sq.^2$$ $$ \color{lightskyblue}{3w^2} =243 sq.^2 $$ which option is that?

thank youuuu