Which of the following statements have the same result? Explain each step in solving each one. I. f(2) when f(x) = 3x + 2 II. fâ1(3) when f(x) = 2 x minus 7, all over 3 III. 2y + 14 = 4y â 2
Please help very important :)
Well, you plug in the values of x, into the equation For example for the first one it's f(2) which is x=2 -> 3(2) + 2 = ....? For the third one 2y+14=4y-2 combine thelike terms to one side, make the y values on the right side, x values on the left side, and solve for y For the second one -> \(3=\frac{2x-7}{3}\) and then solve for x If you're confused o-0 tell me
which ones have the same result?
I can't solve it for you, it would be against the rules; but if you reread what i wrote, I think that you can get to the answer yourself
ok thank you!
yw~
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