Question

Look at the figure:

An image of a right triangle is shown with an angle labeled x.

If tan x° = a divided by 4 and cos x° = 4 divided by b what is the value of sin x°? (1 point)


sin x° = 4b
sin x° = b over a
sin x° = 4a
sin x° = a over b

Answer 1

Please post the image that goes along with the question.

Answer 2

Take your best academic guess, I will correct you on the way.

Answer 3

c

Answer 4

Why, what makes it correct in your mind?

Answer 5

nothing

Answer 6

So, why did you pick C.)?

Answer 7

because it looked the most right

Answer 8

@karlottalotta
\(tan(\theta)=\frac{opposite}{adjacent}\) so then we have (the following picture)
do you understand so far?

Answer 9

\[cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(x)=\frac{4}{b}\]

Answer 10

So now we have the sides

Answer 11

And then we want sin(x)
\[sin(\theta)=\frac{opposite}{hypotenuse}\]
sin(x) = (the following picture because I can't give a direct answer)
opposite side: a
hypotenuse side: b
so sin(x) is...?

Answer 12

thanks for the help

Answer 13

yw~