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help pls ;-; ss below
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The distributive property says \(a(b+c) = a(b)+a(c)\) and \(a(b-c) = a(b)-a(c)\) \[-2(u+6)-6u=4(u+3)\] \[ −2u+(−12)+−6u=4u+12 \] \[ (−2u+−6u)+(−12)=4u+12 \] \[ −8u+(−12)=4u+12 \] \[ −8u−12−4u=+12 \] \[ −12u−12=12 \] \[ -12y=12+12 \] \[ −12u=24 \] \[ u=\frac{24}{-12} \] \[ u=(-2) \]
ooh now i know why i got it wrong
\[ -3(x+5)+5x=2(x-6) \] \[ −3x+(−15)+5x=2x+−12 \] \[ (−3x+5x)+(−15)=2x−12 \] \[ 2x-15=2x−12 \] \[ 2x−15−2x=−12 \] \[ −15=−12 \] \[ 0=-12+15 \] \[ 0=3 \] do you think that's true?
no cus 3 cant equal 0
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yep so what's the answer
oh you're right- xd
no solution right?
yea
ok
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